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7a^2-12a-4=0
a = 7; b = -12; c = -4;
Δ = b2-4ac
Δ = -122-4·7·(-4)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-16}{2*7}=\frac{-4}{14} =-2/7 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+16}{2*7}=\frac{28}{14} =2 $
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